What are the solutions to the equation n^2-4=4 ?

The solutions to the equation n^2-4=4 are n=2sqrt(2),n=-2sqrt(2)

Find the zeros of n^2-4=4

The zeros of n^2-4=4 are n=2sqrt(2),n=-2sqrt(2)

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n^{2} - 4 = 4

n = 22, n = - 22

Decimal Notation

n = 2.82842 \dots, n = - 2.82842 \dots

Solution steps

n^{2} - 4 = 4

Move

4

to the right side

n^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 8, n = - 8

8 = 22

- 8 = - 22

n = 22, n = - 22

w \frac{5 w + 4}{3} = \frac{3 w}{2}

(k + 4)^{2} = 25

x, f (x - 3) = x^{2} + 9 x + 5

104 = u^{2} - 5 u

(x - 2)^{2} + (x + 2)^{2} = 0

What are the solutions to the equation n^2-4=4 ?
The solutions to the equation n^2-4=4 are n=2sqrt(2),n=-2sqrt(2)
Find the zeros of n^2-4=4
The zeros of n^2-4=4 are n=2sqrt(2),n=-2sqrt(2)