What are the solutions to the equation (x-2)^2+(x+2)^2=0 ?

The solutions to the equation (x-2)^2+(x+2)^2=0 are x=2i,x=-2i

Find the zeros of (x-2)^2+(x+2)^2=0

The zeros of (x-2)^2+(x+2)^2=0 are x=2i,x=-2i

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(x - 2)^{2} + (x + 2)^{2} = 0

x = 2 i, x = - 2 i

Solution steps

(x - 2)^{2} + (x + 2)^{2} = 0

Expand

(x - 2)^{2} + (x + 2)^{2} : 2 x^{2} + 8

2 x^{2} + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

0^{2} - 4 \cdot 2 \cdot 8 : 8 i

x_{1, 2} = \frac{- 0 \pm 8 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 8 i}{2 \cdot 2}, x_{2} = \frac{- 0 - 8 i}{2 \cdot 2}

x = \frac{- 0 + 8 i}{2 \cdot 2} : 2 i

x = \frac{- 0 - 8 i}{2 \cdot 2} : - 2 i

The solutions to the quadratic equation are:

x = 2 i, x = - 2 i

- x^{2} - 2 x + 19 = 0

x^{2} + 4 x + 64 = 0

(7 - x) (- 3 - x) + 26 = 0

3 x^{2} - 6 x + 5 = 0

2 x^{2} - 28 = x (x - 3)

What are the solutions to the equation (x-2)^2+(x+2)^2=0 ?
The solutions to the equation (x-2)^2+(x+2)^2=0 are x=2i,x=-2i
Find the zeros of (x-2)^2+(x+2)^2=0
The zeros of (x-2)^2+(x+2)^2=0 are x=2i,x=-2i