What are the solutions to the equation -9x^2+153x-144=0 ?

The solutions to the equation -9x^2+153x-144=0 are x=1,x=16

Find the zeros of -9x^2+153x-144=0

The zeros of -9x^2+153x-144=0 are x=1,x=16

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- 9 x^{2} + 153 x - 144 = 0

x = 1, x = 16

Solution steps

- 9 x^{2} + 153 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 153 \pm 15 3 ^{2} - 4 ( - 9 ) ( - 144 )}{2 ( - 9 )}

15 3^{2} - 4 (- 9) (- 144) = 135

x_{1, 2} = \frac{- 153 \pm 135}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 153 + 135}{2 ( - 9 )}, x_{2} = \frac{- 153 - 135}{2 ( - 9 )}

x = \frac{- 153 + 135}{2 ( - 9 )} : 1

x = \frac{- 153 - 135}{2 ( - 9 )} : 16

The solutions to the quadratic equation are:

x = 1, x = 16

2 x^{2} + 4 x + 30 = 0

x^{2} + 2 x - 0.5 = 0

(x + 2)^{2} + x^{2} = 74

(3 y + 17)^{2} = 50

w^{2} = 8 (w - 4)

What are the solutions to the equation -9x^2+153x-144=0 ?
The solutions to the equation -9x^2+153x-144=0 are x=1,x=16
Find the zeros of -9x^2+153x-144=0
The zeros of -9x^2+153x-144=0 are x=1,x=16