What are the solutions to the equation (x+2)^2+x^2=74 ?

The solutions to the equation (x+2)^2+x^2=74 are x=5,x=-7

Find the zeros of (x+2)^2+x^2=74

The zeros of (x+2)^2+x^2=74 are x=5,x=-7

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(x + 2)^{2} + x^{2} = 74

x = 5, x = - 7

Solution steps

(x + 2)^{2} + x^{2} = 74

Expand

(x + 2)^{2} + x^{2} : 2 x^{2} + 4 x + 4

2 x^{2} + 4 x + 4 = 74

Move

74

to the left side

2 x^{2} + 4 x - 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 70 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 70) = 24

x_{1, 2} = \frac{- 4 \pm 24}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 24}{2 \cdot 2}, x_{2} = \frac{- 4 - 24}{2 \cdot 2}

x = \frac{- 4 + 24}{2 \cdot 2} : 5

x = \frac{- 4 - 24}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

(3 y + 17)^{2} = 50

w^{2} = 8 (w - 4)

a, a b^{2} + a^{2} b + 3 = ab

4 x^{2} + 20 = 4

2 (x - 1)^{2} - 3 = 0

What are the solutions to the equation (x+2)^2+x^2=74 ?
The solutions to the equation (x+2)^2+x^2=74 are x=5,x=-7
Find the zeros of (x+2)^2+x^2=74
The zeros of (x+2)^2+x^2=74 are x=5,x=-7