What are the solutions to the equation 4x=21-x^2 ?

The solutions to the equation 4x=21-x^2 are x=-7,x=3

Find the zeros of 4x=21-x^2

The zeros of 4x=21-x^2 are x=-7,x=3

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4 x = 21 - x^{2}

x = - 7, x = 3

Solution steps

4 x = 21 - x^{2}

Switch sides

21 - x^{2} = 4 x

Move

4 x

to the left side

21 - x^{2} - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 4 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 21}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 21 = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 10}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 10}{2 ( - 1 )} : - 7

x = \frac{- ( - 4 ) - 10}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 7, x = 3

2 n^{2} - 2 n + 7 = 0

(1 - x)^{2} = - 1

4 x^{2} - 32 x + 65 = 0

2 x^{2} + 13 x - 45 = 0

x (x + 8) = 6 x + 7

What are the solutions to the equation 4x=21-x^2 ?
The solutions to the equation 4x=21-x^2 are x=-7,x=3
Find the zeros of 4x=21-x^2
The zeros of 4x=21-x^2 are x=-7,x=3