What are the solutions to the equation (1-x)^2=-1 ?

The solutions to the equation (1-x)^2=-1 are x=-i+1,x=i+1

Find the zeros of (1-x)^2=-1

The zeros of (1-x)^2=-1 are x=-i+1,x=i+1

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(1 - x)^{2} = - 1

x = - i + 1, x = i + 1

Solution steps

(1 - x)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - x = - 1 : x = - i + 1

Solve

1 - x = - - 1 : x = i + 1

The solutions to the quadratic equation are:

x = - i + 1, x = i + 1

4 x^{2} - 32 x + 65 = 0

2 x^{2} + 13 x - 45 = 0

x (x + 8) = 6 x + 7

5 y^{2} + 6 = 16

2 x^{2} - 10 x + 8 = 0

What are the solutions to the equation (1-x)^2=-1 ?
The solutions to the equation (1-x)^2=-1 are x=-i+1,x=i+1
Find the zeros of (1-x)^2=-1
The zeros of (1-x)^2=-1 are x=-i+1,x=i+1