What are the solutions to the equation 2x^2+13x-45=0 ?

The solutions to the equation 2x^2+13x-45=0 are x= 5/2 ,x=-9

Find the zeros of 2x^2+13x-45=0

The zeros of 2x^2+13x-45=0 are x= 5/2 ,x=-9

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2 x^{2} + 13 x - 45 = 0

x = \frac{5}{2}, x = - 9

Solution steps

2 x^{2} + 13 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 45 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 45) = 23

x_{1, 2} = \frac{- 13 \pm 23}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 23}{2 \cdot 2}, x_{2} = \frac{- 13 - 23}{2 \cdot 2}

x = \frac{- 13 + 23}{2 \cdot 2} : \frac{5}{2}

x = \frac{- 13 - 23}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 9

x (x + 8) = 6 x + 7

5 y^{2} + 6 = 16

2 x^{2} - 10 x + 8 = 0

(- \frac{1}{3})^{2} + x^{2} = 1

(x - 4)^{2} - 40 = 0

What are the solutions to the equation 2x^2+13x-45=0 ?
The solutions to the equation 2x^2+13x-45=0 are x= 5/2 ,x=-9
Find the zeros of 2x^2+13x-45=0
The zeros of 2x^2+13x-45=0 are x= 5/2 ,x=-9