What are the solutions to the equation completesquare 2x^2-10x+8=0 ?

The solutions to the equation completesquare 2x^2-10x+8=0 are x=4,x=1

Find the zeros of completesquare 2x^2-10x+8=0

The zeros of completesquare 2x^2-10x+8=0 are x=4,x=1

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2 x^{2} - 10 x + 8 = 0

x = 4, x = 1

Solution steps

2 x^{2} - 10 x + 8 = 0

Move

8

to the right side

2 x^{2} - 10 x = - 8

Divide both sides by

2

\frac{2 x ^{2} - 10 x}{2} = \frac{- 8}{2}

x^{2} - 5 x = - 4

Rewrite in the form

(x + a)^{2} = b

(x - \frac{5}{2})^{2} = \frac{9}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{5}{2} = \frac{9}{4} : x = 4

Solve

x - \frac{5}{2} = - \frac{9}{4} : x = 1

The solutions to the quadratic equation are:

x = 4, x = 1

(- \frac{1}{3})^{2} + x^{2} = 1

(x - 4)^{2} - 40 = 0

2 - x = 2 - (x - 1)^{2}

(x - 4) (x - 1) = 28

x^{2} - 3.5 x - 15 = 0

What are the solutions to the equation completesquare 2x^2-10x+8=0 ?
The solutions to the equation completesquare 2x^2-10x+8=0 are x=4,x=1
Find the zeros of completesquare 2x^2-10x+8=0
The zeros of completesquare 2x^2-10x+8=0 are x=4,x=1