What are the solutions to the equation (-1/3)^2+x^2=1 ?

The solutions to the equation (-1/3)^2+x^2=1 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3

Find the zeros of (-1/3)^2+x^2=1

The zeros of (-1/3)^2+x^2=1 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3

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(- \frac{1}{3})^{2} + x^{2} = 1

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Solution steps

(- \frac{1}{3})^{2} + x^{2} = 1

Expand

(- \frac{1}{3})^{2} + x^{2} : \frac{1}{9} + x^{2}

\frac{1}{9} + x^{2} = 1

Move

\frac{1}{9}

to the right side

x^{2} = 1 - \frac{1}{9}

Simplify

1 - \frac{1}{9} : \frac{8}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{9}, x = - \frac{8}{9}

\frac{8}{9} = \frac{2 2}{3}

- \frac{8}{9} = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

(x - 4)^{2} - 40 = 0

2 - x = 2 - (x - 1)^{2}

(x - 4) (x - 1) = 28

x^{2} - 3.5 x - 15 = 0

3 g^{2} - 12 g = - 4

What are the solutions to the equation (-1/3)^2+x^2=1 ?
The solutions to the equation (-1/3)^2+x^2=1 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3
Find the zeros of (-1/3)^2+x^2=1
The zeros of (-1/3)^2+x^2=1 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3