What are the solutions to the equation factor-x^2+8x=12 ?

The solutions to the equation factor-x^2+8x=12 are x=2,x=6

Find the zeros of factor-x^2+8x=12

The zeros of factor-x^2+8x=12 are x=2,x=6

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- x^{2} + 8 x = 12

x = 2, x = 6

Solution steps

- x^{2} + 8 x = 12

Move

12

to the left side

- x^{2} + 8 x - 12 = 0

Factor

- x^{2} + 8 x - 12 : - (x - 2) (x - 6)

- (x - 2) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = 2, x = 6

- x^{2} = - 3 x - 18

x, f = x^{2} + m x + 3

2 0^{2} + b^{2} = 5 2^{2}

(x + 1)^{2} = 13

(x + 1)^{2} = 15

What are the solutions to the equation factor-x^2+8x=12 ?
The solutions to the equation factor-x^2+8x=12 are x=2,x=6
Find the zeros of factor-x^2+8x=12
The zeros of factor-x^2+8x=12 are x=2,x=6