What are the solutions to the equation 3x^2-5x+2=4-6x ?

The solutions to the equation 3x^2-5x+2=4-6x are x= 2/3 ,x=-1

Find the zeros of 3x^2-5x+2=4-6x

The zeros of 3x^2-5x+2=4-6x are x= 2/3 ,x=-1

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3 x^{2} - 5 x + 2 = 4 - 6 x

x = \frac{2}{3}, x = - 1

Solution steps

3 x^{2} - 5 x + 2 = 4 - 6 x

Move

6 x

to the left side

3 x^{2} + x + 2 = 4

Move

4

to the left side

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

(4 y + 10) (y - 3 y) = 5

x^{2} + 8 x - 4 = 0

3 x^{2} - 4 = - x^{2}

2 - x^{2} + x = 0

x^{2} + 9^{2} = 1 7^{2}

What are the solutions to the equation 3x^2-5x+2=4-6x ?
The solutions to the equation 3x^2-5x+2=4-6x are x= 2/3 ,x=-1
Find the zeros of 3x^2-5x+2=4-6x
The zeros of 3x^2-5x+2=4-6x are x= 2/3 ,x=-1