What are the solutions to the equation completesquare x^2+8x-4=0 ?

The solutions to the equation completesquare x^2+8x-4=0 are x=2sqrt(5)-4,x=-2sqrt(5)-4

Find the zeros of completesquare x^2+8x-4=0

The zeros of completesquare x^2+8x-4=0 are x=2sqrt(5)-4,x=-2sqrt(5)-4

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x^{2} + 8 x - 4 = 0

x = 25 - 4, x = - 25 - 4

Solution steps

x^{2} + 8 x - 4 = 0

Move

4

to the right side

x^{2} + 8 x = 4

Rewrite in the form

(x + a)^{2} = b

(x + 4)^{2} = 20

For

the solutions are

f (x) = a, - a

Solve

x + 4 = 20 : x = 25 - 4

Solve

x + 4 = - 20 : x = - 25 - 4

The solutions to the quadratic equation are:

x = 25 - 4, x = - 25 - 4

3 x^{2} - 4 = - x^{2}

2 - x^{2} + x = 0

x^{2} + 9^{2} = 1 7^{2}

2 x^{2} + 4 x + 4 = 10

- q^{2} + 8 q + 6 = 0

What are the solutions to the equation completesquare x^2+8x-4=0 ?
The solutions to the equation completesquare x^2+8x-4=0 are x=2sqrt(5)-4,x=-2sqrt(5)-4
Find the zeros of completesquare x^2+8x-4=0
The zeros of completesquare x^2+8x-4=0 are x=2sqrt(5)-4,x=-2sqrt(5)-4