What are the solutions to the equation 3x^2-4=-x^2 ?

The solutions to the equation 3x^2-4=-x^2 are x=1,x=-1

Find the zeros of 3x^2-4=-x^2

The zeros of 3x^2-4=-x^2 are x=1,x=-1

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3 x^{2} - 4 = - x^{2}

x = 1, x = - 1

Solution steps

3 x^{2} - 4 = - x^{2}

Move

4

to the right side

3 x^{2} = - x^{2} + 4

Move

x^{2}

to the left side

4 x^{2} = 4

Divide both sides by

4

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

2 - x^{2} + x = 0

x^{2} + 9^{2} = 1 7^{2}

2 x^{2} + 4 x + 4 = 10

- q^{2} + 8 q + 6 = 0

3 x^{2} - 12 x + 14 = 0

What are the solutions to the equation 3x^2-4=-x^2 ?
The solutions to the equation 3x^2-4=-x^2 are x=1,x=-1
Find the zeros of 3x^2-4=-x^2
The zeros of 3x^2-4=-x^2 are x=1,x=-1