What are the solutions to the equation -q^2+8q+6=0 ?

The solutions to the equation -q^2+8q+6=0 are q=4-sqrt(22),q=4+sqrt(22)

Find the zeros of -q^2+8q+6=0

The zeros of -q^2+8q+6=0 are q=4-sqrt(22),q=4+sqrt(22)

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- q^{2} + 8 q + 6 = 0

q = 4 - 22, q = 4 + 22

Solution steps

- q^{2} + 8 q + 6 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 6 = 222

q_{1, 2} = \frac{- 8 \pm 2 22}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- 8 + 2 22}{2 ( - 1 )}, q_{2} = \frac{- 8 - 2 22}{2 ( - 1 )}

q = \frac{- 8 + 2 22}{2 ( - 1 )} : 4 - 22

q = \frac{- 8 - 2 22}{2 ( - 1 )} : 4 + 22

The solutions to the quadratic equation are:

q = 4 - 22, q = 4 + 22

3 x^{2} - 12 x + 14 = 0

0 = 0.5 x^{2} - 10 x + 100

- x^{2} + 5 x + 10 = 0

x^{2} + 9 x + 90 = 0

- \frac{2}{3} x^{2} = 0

What are the solutions to the equation -q^2+8q+6=0 ?
The solutions to the equation -q^2+8q+6=0 are q=4-sqrt(22),q=4+sqrt(22)
Find the zeros of -q^2+8q+6=0
The zeros of -q^2+8q+6=0 are q=4-sqrt(22),q=4+sqrt(22)