What are the solutions to the equation 3x^2+10=-6x ?

The solutions to the equation 3x^2+10=-6x are x=-1+isqrt(7/3),x=-1-isqrt(7/3)

Find the zeros of 3x^2+10=-6x

The zeros of 3x^2+10=-6x are x=-1+isqrt(7/3),x=-1-isqrt(7/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 10 = - 6 x

x = - 1 + i \frac{7}{3}, x = - 1 - i \frac{7}{3}

Solution steps

3 x^{2} + 10 = - 6 x

Move

6 x

to the left side

3 x^{2} + 10 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 10 : 221 i

x_{1, 2} = \frac{- 6 \pm 2 21 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 21 i}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 21 i}{2 \cdot 3}

x = \frac{- 6 + 2 21 i}{2 \cdot 3} : - 1 + i \frac{7}{3}

x = \frac{- 6 - 2 21 i}{2 \cdot 3} : - 1 - i \frac{7}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{7}{3}, x = - 1 - i \frac{7}{3}

x^{2} + 2 + x^{2} + 8 x = 3 x^{2} + 4 x - 10

x, x^{2} + x y = y^{2}

3 x^{2} - 24 x - 100 = 0

39 = x^{2} - 2 x + 4

x, (x + y_{i})^{2} = 3 - 4 i

What are the solutions to the equation 3x^2+10=-6x ?
The solutions to the equation 3x^2+10=-6x are x=-1+isqrt(7/3),x=-1-isqrt(7/3)
Find the zeros of 3x^2+10=-6x
The zeros of 3x^2+10=-6x are x=-1+isqrt(7/3),x=-1-isqrt(7/3)