What are the solutions to the equation 2x^2-9x-9=0 ?

The solutions to the equation 2x^2-9x-9=0 are x=(9+3sqrt(17))/4 ,x=(9-3sqrt(17))/4

Find the zeros of 2x^2-9x-9=0

The zeros of 2x^2-9x-9=0 are x=(9+3sqrt(17))/4 ,x=(9-3sqrt(17))/4

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2 x^{2} - 9 x - 9 = 0

x = \frac{9 + 3 17}{4}, x = \frac{9 - 3 17}{4}

Solution steps

2 x^{2} - 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 9) = 317

x_{1, 2} = \frac{- ( - 9 ) \pm 3 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 17}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 3 17}{2 \cdot 2}

x = \frac{- ( - 9 ) + 3 17}{2 \cdot 2} : \frac{9 + 3 17}{4}

x = \frac{- ( - 9 ) - 3 17}{2 \cdot 2} : \frac{9 - 3 17}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 3 17}{4}, x = \frac{9 - 3 17}{4}

6 x^{2} + 12 x

x^{2} = 2. 5^{2} + 10. 9^{2}

4 x^{2} - 12 x + 9 = 16

97 = 215 x - 16 x^{2}

- 16 x^{2} + 112 x + 128 = 0

What are the solutions to the equation 2x^2-9x-9=0 ?
The solutions to the equation 2x^2-9x-9=0 are x=(9+3sqrt(17))/4 ,x=(9-3sqrt(17))/4
Find the zeros of 2x^2-9x-9=0
The zeros of 2x^2-9x-9=0 are x=(9+3sqrt(17))/4 ,x=(9-3sqrt(17))/4