What are the solutions to the equation 4x^2-12x+9=16 ?

The solutions to the equation 4x^2-12x+9=16 are x= 7/2 ,x=-1/2

Find the zeros of 4x^2-12x+9=16

The zeros of 4x^2-12x+9=16 are x= 7/2 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 12 x + 9 = 16

x = \frac{7}{2}, x = - \frac{1}{2}

Solution steps

4 x^{2} - 12 x + 9 = 16

Move

16

to the left side

4 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 7) = 16

x_{1, 2} = \frac{- ( - 12 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 16}{2 \cdot 4}

x = \frac{- ( - 12 ) + 16}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 12 ) - 16}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{1}{2}

97 = 215 x - 16 x^{2}

- 16 x^{2} + 112 x + 128 = 0

n = t^{2} - 12

x^{2} - 2 = 7 x - x^{2}

x^{2} + 12 x - 72 = 0

What are the solutions to the equation 4x^2-12x+9=16 ?
The solutions to the equation 4x^2-12x+9=16 are x= 7/2 ,x=-1/2
Find the zeros of 4x^2-12x+9=16
The zeros of 4x^2-12x+9=16 are x= 7/2 ,x=-1/2