What are the solutions to the equation 2m^2+17m-9=0 ?

The solutions to the equation 2m^2+17m-9=0 are m= 1/2 ,m=-9

Find the zeros of 2m^2+17m-9=0

The zeros of 2m^2+17m-9=0 are m= 1/2 ,m=-9

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2 m^{2} + 17 m - 9 = 0

m = \frac{1}{2}, m = - 9

Decimal Notation

m = 0.5, m = - 9

Solution steps

2 m^{2} + 17 m - 9 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

1 7^{2} - 4 \cdot 2 (- 9) = 19

m_{1, 2} = \frac{- 17 \pm 19}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 17 + 19}{2 \cdot 2}, m_{2} = \frac{- 17 - 19}{2 \cdot 2}

m = \frac{- 17 + 19}{2 \cdot 2} : \frac{1}{2}

m = \frac{- 17 - 19}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

m = \frac{1}{2}, m = - 9

(3 x - 2) (x + 7) = 0

x^{2} + 3 x = 18

a^{2} - 6 a - 7 = 0

x, 5 x^{2} - 20 x = 0

x, y x^{2} = 3 x^{2} - 8 x + 4

What are the solutions to the equation 2m^2+17m-9=0 ?
The solutions to the equation 2m^2+17m-9=0 are m= 1/2 ,m=-9
Find the zeros of 2m^2+17m-9=0
The zeros of 2m^2+17m-9=0 are m= 1/2 ,m=-9