What are the solutions to the equation 4x*(2x+4)=-8 ?

The solutions to the equation 4x*(2x+4)=-8 are x=-1

Find the zeros of 4x*(2x+4)=-8

The zeros of 4x*(2x+4)=-8 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x \cdot (2 x + 4) = - 8

x = - 1

Solution steps

4 x (2 x + 4) = - 8

Expand

4 x (2 x + 4) : 8 x^{2} + 16 x

8 x^{2} + 16 x = - 8

Move

8

to the left side

8 x^{2} + 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 \cdot 8}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 \cdot 8 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 8}

x = \frac{- 16}{2 \cdot 8}

\frac{- 16}{2 \cdot 8} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

2 x^{2} - 7 x = 12

6 x^{2} + 8 = - 16

x^{2} - 2 x - 1 = - 1

2 q^{2} + q - 1596 = 0

x, T (x) = x^{2} + 30 x + 200

What are the solutions to the equation 4x*(2x+4)=-8 ?
The solutions to the equation 4x*(2x+4)=-8 are x=-1
Find the zeros of 4x*(2x+4)=-8
The zeros of 4x*(2x+4)=-8 are x=-1