What are the solutions to the equation n^2+14n-5=0 ?

The solutions to the equation n^2+14n-5=0 are n=-7+3sqrt(6),n=-7-3sqrt(6)

Find the zeros of n^2+14n-5=0

The zeros of n^2+14n-5=0 are n=-7+3sqrt(6),n=-7-3sqrt(6)

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n^{2} + 14 n - 5 = 0

n = - 7 + 36, n = - 7 - 36

Solution steps

n^{2} + 14 n - 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 5) = 66

n_{1, 2} = \frac{- 14 \pm 6 6}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 14 + 6 6}{2 \cdot 1}, n_{2} = \frac{- 14 - 6 6}{2 \cdot 1}

n = \frac{- 14 + 6 6}{2 \cdot 1} : - 7 + 36

n = \frac{- 14 - 6 6}{2 \cdot 1} : - 7 - 36

The solutions to the quadratic equation are:

n = - 7 + 36, n = - 7 - 36

x^{2} = 10 x - 20

x^{2} = 10 x - 10

25 - 16 x^{2} = 0

x, p = 3 (y + 2 x)^{2}

x, 3 x^{2} y = 75

What are the solutions to the equation n^2+14n-5=0 ?
The solutions to the equation n^2+14n-5=0 are n=-7+3sqrt(6),n=-7-3sqrt(6)
Find the zeros of n^2+14n-5=0
The zeros of n^2+14n-5=0 are n=-7+3sqrt(6),n=-7-3sqrt(6)