What are the solutions to the equation x^2+x-6=-4 ?

The solutions to the equation x^2+x-6=-4 are x=1,x=-2

Find the zeros of x^2+x-6=-4

The zeros of x^2+x-6=-4 are x=1,x=-2

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x^{2} + x - 6 = - 4

x = 1, x = - 2

Solution steps

x^{2} + x - 6 = - 4

Move

4

to the left side

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

x^{2} + 7 x + 3 = 33

9 x^{2} + 6 x = - 15

3 (z + 11)^{2} - 10 = 110

3 b^{2} - 7 b - 10 = 0

x^{2} - 16 x - 48 = 0

What are the solutions to the equation x^2+x-6=-4 ?
The solutions to the equation x^2+x-6=-4 are x=1,x=-2
Find the zeros of x^2+x-6=-4
The zeros of x^2+x-6=-4 are x=1,x=-2