What are the solutions to the equation 2x^2+5x-11=0 ?

The solutions to the equation 2x^2+5x-11=0 are x=(-5+sqrt(113))/4 ,x=(-5-sqrt(113))/4

Find the zeros of 2x^2+5x-11=0

The zeros of 2x^2+5x-11=0 are x=(-5+sqrt(113))/4 ,x=(-5-sqrt(113))/4

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2 x^{2} + 5 x - 11 = 0

x = \frac{- 5 + 113}{4}, x = \frac{- 5 - 113}{4}

Decimal Notation

x = 1.40753 \dots, x = - 3.90753 \dots

Solution steps

2 x^{2} + 5 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 11) = 113

x_{1, 2} = \frac{- 5 \pm 113}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 113}{2 \cdot 2}, x_{2} = \frac{- 5 - 113}{2 \cdot 2}

x = \frac{- 5 + 113}{2 \cdot 2} : \frac{- 5 + 113}{4}

x = \frac{- 5 - 113}{2 \cdot 2} : \frac{- 5 - 113}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 113}{4}, x = \frac{- 5 - 113}{4}

5 x^{2} - 4 x - 8 = 0

0.3 x^{2} - 1.2 x - 0.3 = 0

\frac{3}{8} x^{2} + 3 x + 24 = 0

x, x^{2} y - x^{2} - y = 0

4 x^{2} - 32 x + 8 = 12

What are the solutions to the equation 2x^2+5x-11=0 ?
The solutions to the equation 2x^2+5x-11=0 are x=(-5+sqrt(113))/4 ,x=(-5-sqrt(113))/4
Find the zeros of 2x^2+5x-11=0
The zeros of 2x^2+5x-11=0 are x=(-5+sqrt(113))/4 ,x=(-5-sqrt(113))/4