What are the solutions to the equation 5x^2+x=3 ?

The solutions to the equation 5x^2+x=3 are x=(-1+sqrt(61))/(10),x=(-1-sqrt(61))/(10)

Find the zeros of 5x^2+x=3

The zeros of 5x^2+x=3 are x=(-1+sqrt(61))/(10),x=(-1-sqrt(61))/(10)

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5 x^{2} + x = 3

x = \frac{- 1 + 61}{10}, x = \frac{- 1 - 61}{10}

Decimal Notation

x = 0.68102 \dots, x = - 0.88102 \dots

Solution steps

5 x^{2} + x = 3

Move

3

to the left side

5 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 3) = 61

x_{1, 2} = \frac{- 1 \pm 61}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 61}{2 \cdot 5}, x_{2} = \frac{- 1 - 61}{2 \cdot 5}

x = \frac{- 1 + 61}{2 \cdot 5} : \frac{- 1 + 61}{10}

x = \frac{- 1 - 61}{2 \cdot 5} : \frac{- 1 - 61}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 61}{10}, x = \frac{- 1 - 61}{10}

x^{2} - 14 x - 150 = 201

(x + 3) (x - 2) = 4

3 w^{2} - 84 = 0

2 x^{2} - 17 x - 30 = 0

- 90 x^{2} + 1530 x - 6300 = 0

What are the solutions to the equation 5x^2+x=3 ?
The solutions to the equation 5x^2+x=3 are x=(-1+sqrt(61))/(10),x=(-1-sqrt(61))/(10)
Find the zeros of 5x^2+x=3
The zeros of 5x^2+x=3 are x=(-1+sqrt(61))/(10),x=(-1-sqrt(61))/(10)