What are the solutions to the equation x^2-14x-150=201 ?

The solutions to the equation x^2-14x-150=201 are x=27,x=-13

Find the zeros of x^2-14x-150=201

The zeros of x^2-14x-150=201 are x=27,x=-13

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x^{2} - 14 x - 150 = 201

x = 27, x = - 13

Solution steps

x^{2} - 14 x - 150 = 201

Move

201

to the left side

x^{2} - 14 x - 351 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 351 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 351) = 40

x_{1, 2} = \frac{- ( - 14 ) \pm 40}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 40}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 40}{2 \cdot 1}

x = \frac{- ( - 14 ) + 40}{2 \cdot 1} : 27

x = \frac{- ( - 14 ) - 40}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 27, x = - 13

(x + 3) (x - 2) = 4

3 w^{2} - 84 = 0

2 x^{2} - 17 x - 30 = 0

- 90 x^{2} + 1530 x - 6300 = 0

300 = x^{2} + 2 x

What are the solutions to the equation x^2-14x-150=201 ?
The solutions to the equation x^2-14x-150=201 are x=27,x=-13
Find the zeros of x^2-14x-150=201
The zeros of x^2-14x-150=201 are x=27,x=-13