What are the solutions to the equation 9x^2-53x+49=0 ?

The solutions to the equation 9x^2-53x+49=0 are x=(53+sqrt(1045))/(18),x=(53-sqrt(1045))/(18)

Find the zeros of 9x^2-53x+49=0

The zeros of 9x^2-53x+49=0 are x=(53+sqrt(1045))/(18),x=(53-sqrt(1045))/(18)

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9 x^{2} - 53 x + 49 = 0

x = \frac{53 + 1045}{18}, x = \frac{53 - 1045}{18}

Decimal Notation

x = 4.74035 \dots, x = 1.14853 \dots

Solution steps

9 x^{2} - 53 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 53 ) \pm ( - 53 ) ^{2} - 4 \cdot 9 \cdot 49}{2 \cdot 9}

(- 53)^{2} - 4 \cdot 9 \cdot 49 = 1045

x_{1, 2} = \frac{- ( - 53 ) \pm 1045}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 53 ) + 1045}{2 \cdot 9}, x_{2} = \frac{- ( - 53 ) - 1045}{2 \cdot 9}

x = \frac{- ( - 53 ) + 1045}{2 \cdot 9} : \frac{53 + 1045}{18}

x = \frac{- ( - 53 ) - 1045}{2 \cdot 9} : \frac{53 - 1045}{18}

The solutions to the quadratic equation are:

x = \frac{53 + 1045}{18}, x = \frac{53 - 1045}{18}

4 b^{2} + 16 b - 19 = - 10

(x - 2) \cdot (x - 1) = 0

\frac{1}{2} x^{2} + 5 x - 12 = 0

(x + 1) (3 x - 5) = (5 x - 3) \cdot 4

r, z = r^{2}

What are the solutions to the equation 9x^2-53x+49=0 ?
The solutions to the equation 9x^2-53x+49=0 are x=(53+sqrt(1045))/(18),x=(53-sqrt(1045))/(18)
Find the zeros of 9x^2-53x+49=0
The zeros of 9x^2-53x+49=0 are x=(53+sqrt(1045))/(18),x=(53-sqrt(1045))/(18)