What are the solutions to the equation 5x^2+10x+25=0 ?

The solutions to the equation 5x^2+10x+25=0 are x=-1+2i,x=-1-2i

Find the zeros of 5x^2+10x+25=0

The zeros of 5x^2+10x+25=0 are x=-1+2i,x=-1-2i

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5 x^{2} + 10 x + 25 = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

5 x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 25}{2 \cdot 5}

Simplify

1 0^{2} - 4 \cdot 5 \cdot 25 : 20 i

x_{1, 2} = \frac{- 10 \pm 20 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 20 i}{2 \cdot 5}, x_{2} = \frac{- 10 - 20 i}{2 \cdot 5}

x = \frac{- 10 + 20 i}{2 \cdot 5} : - 1 + 2 i

x = \frac{- 10 - 20 i}{2 \cdot 5} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

2 x^{2} + 10 x = 2

800 = \frac{n}{2} (30 + (n - 1) 10)

(8 + x) \cdot 3 x - (8 + x) \cdot 7 = 0

c^{2} - 32 = 0

3 x^{2} + x - 1 = (2 x + 9) (x - 1)

What are the solutions to the equation 5x^2+10x+25=0 ?
The solutions to the equation 5x^2+10x+25=0 are x=-1+2i,x=-1-2i
Find the zeros of 5x^2+10x+25=0
The zeros of 5x^2+10x+25=0 are x=-1+2i,x=-1-2i