What are the solutions to the equation 2r^2+6r=-12-2r ?

The solutions to the equation 2r^2+6r=-12-2r are r=-2+sqrt(2)i,r=-2-sqrt(2)i

Find the zeros of 2r^2+6r=-12-2r

The zeros of 2r^2+6r=-12-2r are r=-2+sqrt(2)i,r=-2-sqrt(2)i

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2 r^{2} + 6 r = - 12 - 2 r

r = - 2 + 2 i, r = - 2 - 2 i

Solution steps

2 r^{2} + 6 r = - 12 - 2 r

Move

2 r

to the left side

2 r^{2} + 8 r = - 12

Move

12

to the left side

2 r^{2} + 8 r + 12 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

8^{2} - 4 \cdot 2 \cdot 12 : 42 i

r_{1, 2} = \frac{- 8 \pm 4 2 i}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 8 + 4 2 i}{2 \cdot 2}, r_{2} = \frac{- 8 - 4 2 i}{2 \cdot 2}

r = \frac{- 8 + 4 2 i}{2 \cdot 2} : - 2 + 2 i

r = \frac{- 8 - 4 2 i}{2 \cdot 2} : - 2 - 2 i

The solutions to the quadratic equation are:

r = - 2 + 2 i, r = - 2 - 2 i

5 (x + 5)^{2} = 60

(x - 3)^{3} = x^{3} - 63

x^{2} + 16 x = 7

m^{2} - 4 m = 5

- 2 x^{2} - 7 x - 1 = 0

What are the solutions to the equation 2r^2+6r=-12-2r ?
The solutions to the equation 2r^2+6r=-12-2r are r=-2+sqrt(2)i,r=-2-sqrt(2)i
Find the zeros of 2r^2+6r=-12-2r
The zeros of 2r^2+6r=-12-2r are r=-2+sqrt(2)i,r=-2-sqrt(2)i