What are the solutions to the equation 7x+2=-3x^2 ?

The solutions to the equation 7x+2=-3x^2 are x=-2,x=-1/3

Find the zeros of 7x+2=-3x^2

The zeros of 7x+2=-3x^2 are x=-2,x=-1/3

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7 x + 2 = - 3 x^{2}

x = - 2, x = - \frac{1}{3}

Decimal Notation

x = - 2, x = - 0.33333 \dots

Solution steps

7 x + 2 = - 3 x^{2}

Switch sides

- 3 x^{2} = 7 x + 2

Move

2

to the left side

- 3 x^{2} - 2 = 7 x

Move

7 x

to the left side

- 3 x^{2} - 2 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

(- 7)^{2} - 4 (- 3) (- 2) = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 ( - 3 )}, x_{2} = \frac{- ( - 7 ) - 5}{2 ( - 3 )}

x = \frac{- ( - 7 ) + 5}{2 ( - 3 )} : - 2

x = \frac{- ( - 7 ) - 5}{2 ( - 3 )} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = - 2, x = - \frac{1}{3}

3 x^{2} - x - 9 = 0

- 8 x^{2} - 62 x + 16 = 0

(4 + 3 y)^{2} + y^{2} = 146

x, x^{2} y - x = 4 y

- x^{2} + 4 x = 0

What are the solutions to the equation 7x+2=-3x^2 ?
The solutions to the equation 7x+2=-3x^2 are x=-2,x=-1/3
Find the zeros of 7x+2=-3x^2
The zeros of 7x+2=-3x^2 are x=-2,x=-1/3