What are the solutions to the equation 1x^2+3x-4=0 ?

The solutions to the equation 1x^2+3x-4=0 are x=1,x=-4

Find the zeros of 1x^2+3x-4=0

The zeros of 1x^2+3x-4=0 are x=1,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 x^{2} + 3 x - 4 = 0

x = 1, x = - 4

Solution steps

1 \cdot x^{2} + 3 x - 4 = 0

Refine

x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 1}, x_{2} = \frac{- 3 - 5}{2 \cdot 1}

x = \frac{- 3 + 5}{2 \cdot 1} : 1

x = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

x, 4 x^{2} - y^{2} = c

x^{2} + 4 x - 120 = 0

12 x^{2} + 8 = 20 x

3 t^{2} - 12 t - 36 = 0

(x) = 50000 + 200 x + 0.3 x^{2}

What are the solutions to the equation 1x^2+3x-4=0 ?
The solutions to the equation 1x^2+3x-4=0 are x=1,x=-4
Find the zeros of 1x^2+3x-4=0
The zeros of 1x^2+3x-4=0 are x=1,x=-4