What are the solutions to the equation 4u^2-5u-9=0 ?

The solutions to the equation 4u^2-5u-9=0 are u= 9/4 ,u=-1

Find the zeros of 4u^2-5u-9=0

The zeros of 4u^2-5u-9=0 are u= 9/4 ,u=-1

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4 u^{2} - 5 u - 9 = 0

u = \frac{9}{4}, u = - 1

Decimal Notation

u = 2.25, u = - 1

Solution steps

4 u^{2} - 5 u - 9 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 9) = 13

u_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 4}, u_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 4}

u = \frac{- ( - 5 ) + 13}{2 \cdot 4} : \frac{9}{4}

u = \frac{- ( - 5 ) - 13}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

u = \frac{9}{4}, u = - 1

100 = 20 t + \frac{1}{2} 0.2 t^{2}

7 x^{2} + 7 = 0

5 x^{2} - 6 = - x

3 x^{2} - 96 x - 92 = 0

x^{2} + 20 x + 5

What are the solutions to the equation 4u^2-5u-9=0 ?
The solutions to the equation 4u^2-5u-9=0 are u= 9/4 ,u=-1
Find the zeros of 4u^2-5u-9=0
The zeros of 4u^2-5u-9=0 are u= 9/4 ,u=-1