What are the solutions to the equation 5x^2-6=-x ?

The solutions to the equation 5x^2-6=-x are x=1,x=-6/5

Find the zeros of 5x^2-6=-x

The zeros of 5x^2-6=-x are x=1,x=-6/5

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5 x^{2} - 6 = - x

x = 1, x = - \frac{6}{5}

Decimal Notation

x = 1, x = - 1.2

Solution steps

5 x^{2} - 6 = - x

Move

x

to the left side

5 x^{2} - 6 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 6) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 5}, x_{2} = \frac{- 1 - 11}{2 \cdot 5}

x = \frac{- 1 + 11}{2 \cdot 5} : 1

x = \frac{- 1 - 11}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{6}{5}

3 x^{2} - 96 x - 92 = 0

x^{2} + 20 x + 5

x (400 - x) = 10000

12 = x (x + 3)

k^{2} - 2 k - 8 = 0

What are the solutions to the equation 5x^2-6=-x ?
The solutions to the equation 5x^2-6=-x are x=1,x=-6/5
Find the zeros of 5x^2-6=-x
The zeros of 5x^2-6=-x are x=1,x=-6/5