What are the solutions to the equation 7p^2=-3+5p ?

The solutions to the equation 7p^2=-3+5p are p= 5/14+i(sqrt(59))/(14),p= 5/14-i(sqrt(59))/(14)

Find the zeros of 7p^2=-3+5p

The zeros of 7p^2=-3+5p are p= 5/14+i(sqrt(59))/(14),p= 5/14-i(sqrt(59))/(14)

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7 p^{2} = - 3 + 5 p

p = \frac{5}{14} + i \frac{59}{14}, p = \frac{5}{14} - i \frac{59}{14}

Solution steps

7 p^{2} = - 3 + 5 p

Move

5 p

to the left side

7 p^{2} - 5 p = - 3

Move

3

to the left side

7 p^{2} - 5 p + 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

Simplify

(- 5)^{2} - 4 \cdot 7 \cdot 3 : 59 i

p_{1, 2} = \frac{- ( - 5 ) \pm 59 i}{2 \cdot 7}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 59 i}{2 \cdot 7}, p_{2} = \frac{- ( - 5 ) - 59 i}{2 \cdot 7}

p = \frac{- ( - 5 ) + 59 i}{2 \cdot 7} : \frac{5}{14} + i \frac{59}{14}

p = \frac{- ( - 5 ) - 59 i}{2 \cdot 7} : \frac{5}{14} - i \frac{59}{14}

The solutions to the quadratic equation are:

p = \frac{5}{14} + i \frac{59}{14}, p = \frac{5}{14} - i \frac{59}{14}

2 x^{2} + 12 x = 9

(x) = 120 x - 40 x^{2}

X^{2} - 9 X + 14 = 0

2 y^{2} - y + 6 = 0

a^{2} - 12 a = - 27

What are the solutions to the equation 7p^2=-3+5p ?
The solutions to the equation 7p^2=-3+5p are p= 5/14+i(sqrt(59))/(14),p= 5/14-i(sqrt(59))/(14)
Find the zeros of 7p^2=-3+5p
The zeros of 7p^2=-3+5p are p= 5/14+i(sqrt(59))/(14),p= 5/14-i(sqrt(59))/(14)