What are the solutions to the equation 12x+9=-4x^2 ?

The solutions to the equation 12x+9=-4x^2 are x=-3/2

Find the zeros of 12x+9=-4x^2

The zeros of 12x+9=-4x^2 are x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x + 9 = - 4 x^{2}

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

12 x + 9 = - 4 x^{2}

Switch sides

- 4 x^{2} = 12 x + 9

Move

9

to the left side

- 4 x^{2} - 9 = 12 x

Move

12 x

to the left side

- 4 x^{2} - 9 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

(- 12)^{2} - 4 (- 4) (- 9) = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 ( - 4 )}

x = \frac{- ( - 12 )}{2 ( - 4 )}

\frac{- ( - 12 )}{2 ( - 4 )} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

5 t^{2} - 11 t = 12

x + 3 x + 1.5 x 44 x - 2 = 169

7 x^{2} + 54 x - 16 = 0

6 n^{2} + 40 = 70

n^{2} = - 3 n + 40

What are the solutions to the equation 12x+9=-4x^2 ?
The solutions to the equation 12x+9=-4x^2 are x=-3/2
Find the zeros of 12x+9=-4x^2
The zeros of 12x+9=-4x^2 are x=-3/2