What are the solutions to the equation 5x^2+32=57 ?

The solutions to the equation 5x^2+32=57 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 5x^2+32=57

The zeros of 5x^2+32=57 are x=sqrt(5),x=-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 32 = 57

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

5 x^{2} + 32 = 57

Move

32

to the right side

5 x^{2} = 25

Divide both sides by

5

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

3 x^{2} - 6 x - 246 = 0

4.2 x + 8.6 + (- 3.3) x^{2} = 0

3 x^{2} - 45 x + 168 = 0

x^{2} + 4 x + 3 = 1

6 x^{2} = x^{2} + 11

What are the solutions to the equation 5x^2+32=57 ?
The solutions to the equation 5x^2+32=57 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 5x^2+32=57
The zeros of 5x^2+32=57 are x=sqrt(5),x=-sqrt(5)