What are the solutions to the equation x^2+4x+3=1 ?

The solutions to the equation x^2+4x+3=1 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of x^2+4x+3=1

The zeros of x^2+4x+3=1 are x=-2+sqrt(2),x=-2-sqrt(2)

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x^{2} + 4 x + 3 = 1

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

x^{2} + 4 x + 3 = 1

Move

1

to the left side

x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

x = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

x = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

6 x^{2} = x^{2} + 11

- x^{2} - 5 x + 10 = 0

x^{2} + 2 x - 18

x^{2} (- 8 b + 7) = - 8 b + 6

x, x (x - 5) = 0

What are the solutions to the equation x^2+4x+3=1 ?
The solutions to the equation x^2+4x+3=1 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of x^2+4x+3=1
The zeros of x^2+4x+3=1 are x=-2+sqrt(2),x=-2-sqrt(2)