What are the solutions to the equation 15a^2+18a+3=4a ?

The solutions to the equation 15a^2+18a+3=4a are a=-1/3 ,a=-3/5

Find the zeros of 15a^2+18a+3=4a

The zeros of 15a^2+18a+3=4a are a=-1/3 ,a=-3/5

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15 a^{2} + 18 a + 3 = 4 a

a = - \frac{1}{3}, a = - \frac{3}{5}

Decimal Notation

a = - 0.33333 \dots, a = - 0.6

Solution steps

15 a^{2} + 18 a + 3 = 4 a

Move

4 a

to the left side

15 a^{2} + 14 a + 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 15 \cdot 3}{2 \cdot 15}

1 4^{2} - 4 \cdot 15 \cdot 3 = 4

a_{1, 2} = \frac{- 14 \pm 4}{2 \cdot 15}

Separate the solutions

a_{1} = \frac{- 14 + 4}{2 \cdot 15}, a_{2} = \frac{- 14 - 4}{2 \cdot 15}

a = \frac{- 14 + 4}{2 \cdot 15} : - \frac{1}{3}

a = \frac{- 14 - 4}{2 \cdot 15} : - \frac{3}{5}

The solutions to the quadratic equation are:

a = - \frac{1}{3}, a = - \frac{3}{5}

x, y^{2} = 3 (x - h)^{2}

x^{2} = 342

m^{2} - m - 20 = 0

x^{2} + 5 x^{2} = - 4

(12 t^{2} - 10 t + 5) + (10 t - 15) = 0

What are the solutions to the equation 15a^2+18a+3=4a ?
The solutions to the equation 15a^2+18a+3=4a are a=-1/3 ,a=-3/5
Find the zeros of 15a^2+18a+3=4a
The zeros of 15a^2+18a+3=4a are a=-1/3 ,a=-3/5