What are the solutions to the equation 16x(4x-3)=-9 ?

The solutions to the equation 16x(4x-3)=-9 are x= 3/8

Find the zeros of 16x(4x-3)=-9

The zeros of 16x(4x-3)=-9 are x= 3/8

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16 x (4 x - 3) = - 9

x = \frac{3}{8}

Decimal Notation

x = 0.375

Solution steps

16 x (4 x - 3) = - 9

Expand

16 x (4 x - 3) : 64 x^{2} - 48 x

64 x^{2} - 48 x = - 9

Move

9

to the left side

64 x^{2} - 48 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 64 \cdot 9}{2 \cdot 64}

(- 48)^{2} - 4 \cdot 64 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 64}

x = \frac{- ( - 48 )}{2 \cdot 64}

\frac{- ( - 48 )}{2 \cdot 64} = \frac{3}{8}

x = \frac{3}{8}

The solution to the quadratic equation is:

x = \frac{3}{8}

2 (x^{2} - 4) + 3 (x^{2} + 5) = 8 x - 3

15 a^{2} + 18 a + 3 = 4 a

x, y^{2} = 3 (x - h)^{2}

x^{2} = 342

m^{2} - m - 20 = 0

What are the solutions to the equation 16x(4x-3)=-9 ?
The solutions to the equation 16x(4x-3)=-9 are x= 3/8
Find the zeros of 16x(4x-3)=-9
The zeros of 16x(4x-3)=-9 are x= 3/8