What are the solutions to the equation 4x^2+24x+227=0 ?

The solutions to the equation 4x^2+24x+227=0 are x=-3+i(sqrt(191))/2 ,x=-3-i(sqrt(191))/2

Find the zeros of 4x^2+24x+227=0

The zeros of 4x^2+24x+227=0 are x=-3+i(sqrt(191))/2 ,x=-3-i(sqrt(191))/2

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4 x^{2} + 24 x + 227 = 0

x = - 3 + i \frac{191}{2}, x = - 3 - i \frac{191}{2}

Solution steps

4 x^{2} + 24 x + 227 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 227}{2 \cdot 4}

Simplify

2 4^{2} - 4 \cdot 4 \cdot 227 : 4191 i

x_{1, 2} = \frac{- 24 \pm 4 191 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 4 191 i}{2 \cdot 4}, x_{2} = \frac{- 24 - 4 191 i}{2 \cdot 4}

x = \frac{- 24 + 4 191 i}{2 \cdot 4} : - 3 + i \frac{191}{2}

x = \frac{- 24 - 4 191 i}{2 \cdot 4} : - 3 - i \frac{191}{2}

The solutions to the quadratic equation are:

x = - 3 + i \frac{191}{2}, x = - 3 - i \frac{191}{2}

3 x^{2} + 2 x - 4 x^{2} + 11 = 0

4 n^{2} - 720 = 0

x^{2} - 18 = x + 2

3 k^{2} - 4 = 0

x^{2} - 1 - 2 x = 0

What are the solutions to the equation 4x^2+24x+227=0 ?
The solutions to the equation 4x^2+24x+227=0 are x=-3+i(sqrt(191))/2 ,x=-3-i(sqrt(191))/2
Find the zeros of 4x^2+24x+227=0
The zeros of 4x^2+24x+227=0 are x=-3+i(sqrt(191))/2 ,x=-3-i(sqrt(191))/2