What are the solutions to the equation x^2-1-2x=0 ?

The solutions to the equation x^2-1-2x=0 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of x^2-1-2x=0

The zeros of x^2-1-2x=0 are x=1+sqrt(2),x=1-sqrt(2)

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x^{2} - 1 - 2 x = 0

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

x^{2} - 1 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

x = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

198 = 0.1 w^{2} + 2.155 w + 20

x, - x^{2} - y x - 0.05 y = 0

2 k^{2} + 3 k^{2} + 4 k^{2} = 116

3 q^{2} - 112 q + 930 = 0

11.48 = - 0.5 x^{2} + 0.5 x + 15

What are the solutions to the equation x^2-1-2x=0 ?
The solutions to the equation x^2-1-2x=0 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of x^2-1-2x=0
The zeros of x^2-1-2x=0 are x=1+sqrt(2),x=1-sqrt(2)