What are the solutions to the equation 3k^2-4=0 ?

The solutions to the equation 3k^2-4=0 are k= 2/(sqrt(3)),k=-2/(sqrt(3))

Find the zeros of 3k^2-4=0

The zeros of 3k^2-4=0 are k= 2/(sqrt(3)),k=-2/(sqrt(3))

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3 k^{2} - 4 = 0

k = \frac{2}{3}, k = - \frac{2}{3}

Decimal Notation

k = 1.15470 \dots, k = - 1.15470 \dots

Solution steps

3 k^{2} - 4 = 0

Move

4

to the right side

3 k^{2} = 4

Divide both sides by

3

k^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = \frac{4}{3}, k = - \frac{4}{3}

\frac{4}{3} = \frac{2}{3}

- \frac{4}{3} = - \frac{2}{3}

k = \frac{2}{3}, k = - \frac{2}{3}

x^{2} - 1 - 2 x = 0

198 = 0.1 w^{2} + 2.155 w + 20

x, - x^{2} - y x - 0.05 y = 0

2 k^{2} + 3 k^{2} + 4 k^{2} = 116

3 q^{2} - 112 q + 930 = 0

What are the solutions to the equation 3k^2-4=0 ?
The solutions to the equation 3k^2-4=0 are k= 2/(sqrt(3)),k=-2/(sqrt(3))
Find the zeros of 3k^2-4=0
The zeros of 3k^2-4=0 are k= 2/(sqrt(3)),k=-2/(sqrt(3))