What are the solutions to the equation 3q^2-112q+930=0 ?

The solutions to the equation 3q^2-112q+930=0 are q=(56+sqrt(346))/3 ,q=(56-sqrt(346))/3

Find the zeros of 3q^2-112q+930=0

The zeros of 3q^2-112q+930=0 are q=(56+sqrt(346))/3 ,q=(56-sqrt(346))/3

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3 q^{2} - 112 q + 930 = 0

q = \frac{56 + 346}{3}, q = \frac{56 - 346}{3}

Decimal Notation

q = 24.86702 \dots, q = 12.46630 \dots

Solution steps

3 q^{2} - 112 q + 930 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 112 ) \pm ( - 112 ) ^{2} - 4 \cdot 3 \cdot 930}{2 \cdot 3}

(- 112)^{2} - 4 \cdot 3 \cdot 930 = 2346

q_{1, 2} = \frac{- ( - 112 ) \pm 2 346}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 112 ) + 2 346}{2 \cdot 3}, q_{2} = \frac{- ( - 112 ) - 2 346}{2 \cdot 3}

q = \frac{- ( - 112 ) + 2 346}{2 \cdot 3} : \frac{56 + 346}{3}

q = \frac{- ( - 112 ) - 2 346}{2 \cdot 3} : \frac{56 - 346}{3}

The solutions to the quadratic equation are:

q = \frac{56 + 346}{3}, q = \frac{56 - 346}{3}

11.48 = - 0.5 x^{2} + 0.5 x + 15

x (18 - 2 x) = 40

5 x^{2} = 4 x - 5

5 x^{2} = 4 x + 3

a, S = 2 π a^{2} + 2 πah

What are the solutions to the equation 3q^2-112q+930=0 ?
The solutions to the equation 3q^2-112q+930=0 are q=(56+sqrt(346))/3 ,q=(56-sqrt(346))/3
Find the zeros of 3q^2-112q+930=0
The zeros of 3q^2-112q+930=0 are q=(56+sqrt(346))/3 ,q=(56-sqrt(346))/3