What are the solutions to the equation 5y-6+50y^2=0 ?

The solutions to the equation 5y-6+50y^2=0 are y= 3/10 ,y=-2/5

Find the zeros of 5y-6+50y^2=0

The zeros of 5y-6+50y^2=0 are y= 3/10 ,y=-2/5

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5 y - 6 + 50 y^{2} = 0

y = \frac{3}{10}, y = - \frac{2}{5}

Decimal Notation

y = 0.3, y = - 0.4

Solution steps

5 y - 6 + 50 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

50 y^{2} + 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 50 ( - 6 )}{2 \cdot 50}

5^{2} - 4 \cdot 50 (- 6) = 35

y_{1, 2} = \frac{- 5 \pm 35}{2 \cdot 50}

Separate the solutions

y_{1} = \frac{- 5 + 35}{2 \cdot 50}, y_{2} = \frac{- 5 - 35}{2 \cdot 50}

y = \frac{- 5 + 35}{2 \cdot 50} : \frac{3}{10}

y = \frac{- 5 - 35}{2 \cdot 50} : - \frac{2}{5}

The solutions to the quadratic equation are:

y = \frac{3}{10}, y = - \frac{2}{5}

0 = 4 x^{2} - 5 x - 3

2 x^{2} + 6 x + 3 = 3

6 x^{2} - 4 x - 4 = 0

7 y + 3 y^{2} = 20

- 29 = 4 z - 17 z^{2} + 13 z^{2}

What are the solutions to the equation 5y-6+50y^2=0 ?
The solutions to the equation 5y-6+50y^2=0 are y= 3/10 ,y=-2/5
Find the zeros of 5y-6+50y^2=0
The zeros of 5y-6+50y^2=0 are y= 3/10 ,y=-2/5