What are the solutions to the equation h^2=2^2+2sqrt(2.3) ?

The solutions to the equation h^2=2^2+2sqrt(2.3) are h=sqrt(4+2\sqrt{2.3)},h=-sqrt(4+2\sqrt{2.3)}

Find the zeros of h^2=2^2+2sqrt(2.3)

The zeros of h^2=2^2+2sqrt(2.3) are h=sqrt(4+2\sqrt{2.3)},h=-sqrt(4+2\sqrt{2.3)}

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h^{2} = 2^{2} + 2 2.3

h = 4 + 2 2.3, h = - 4 + 2 2.3

Decimal Notation

h = 2.65200 \dots, h = - 2.65200 \dots

Solution steps

h^{2} = 2^{2} + 2 2.3

2^{2} = 4

h^{2} = 4 + 2 2.3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

h = 4 + 2 2.3, h = - 4 + 2 2.3

3 x^{2} + 6 x - 7

x^{2} = 225

5 x^{2} + 4 x = 2 x^{2} + 7 x

x^{2} + 6 x + 3^{2} = 8 + 9

- 0.00188 (x - 251.5)^{2} + 119 = 0

What are the solutions to the equation h^2=2^2+2sqrt(2.3) ?
The solutions to the equation h^2=2^2+2sqrt(2.3) are h=sqrt(4+2\sqrt{2.3)},h=-sqrt(4+2\sqrt{2.3)}
Find the zeros of h^2=2^2+2sqrt(2.3)
The zeros of h^2=2^2+2sqrt(2.3) are h=sqrt(4+2\sqrt{2.3)},h=-sqrt(4+2\sqrt{2.3)}