What are the solutions to the equation 5x^2+4x=2x^2+7x ?

The solutions to the equation 5x^2+4x=2x^2+7x are x=1,x=0

Find the zeros of 5x^2+4x=2x^2+7x

The zeros of 5x^2+4x=2x^2+7x are x=1,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 4 x = 2 x^{2} + 7 x

x = 1, x = 0

Solution steps

5 x^{2} + 4 x = 2 x^{2} + 7 x

Move

7 x

to the left side

5 x^{2} - 3 x = 2 x^{2}

Move

2 x^{2}

to the left side

3 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3}{2 \cdot 3} : 1

x = \frac{- ( - 3 ) - 3}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x^{2} + 6 x + 3^{2} = 8 + 9

- 0.00188 (x - 251.5)^{2} + 119 = 0

x, y^{2} = r^{2} - x^{2}

- \frac{1}{5} x^{2} + 2 x - 4 = 0

- x^{2} - 5 x + 6

What are the solutions to the equation 5x^2+4x=2x^2+7x ?
The solutions to the equation 5x^2+4x=2x^2+7x are x=1,x=0
Find the zeros of 5x^2+4x=2x^2+7x
The zeros of 5x^2+4x=2x^2+7x are x=1,x=0