What are the solutions to the equation x^2=sqrt(225) ?

The solutions to the equation x^2=sqrt(225) are x=sqrt(15),x=-sqrt(15)

Find the zeros of x^2=sqrt(225)

The zeros of x^2=sqrt(225) are x=sqrt(15),x=-sqrt(15)

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x^{2} = 225

x = 15, x = - 15

Decimal Notation

x = 3.87298 \dots, x = - 3.87298 \dots

Solution steps

x^{2} = 225

Simplify

225 : 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 15, x = - 15

5 x^{2} + 4 x = 2 x^{2} + 7 x

x^{2} + 6 x + 3^{2} = 8 + 9

- 0.00188 (x - 251.5)^{2} + 119 = 0

x, y^{2} = r^{2} - x^{2}

- \frac{1}{5} x^{2} + 2 x - 4 = 0

What are the solutions to the equation x^2=sqrt(225) ?
The solutions to the equation x^2=sqrt(225) are x=sqrt(15),x=-sqrt(15)
Find the zeros of x^2=sqrt(225)
The zeros of x^2=sqrt(225) are x=sqrt(15),x=-sqrt(15)