What are the solutions to the equation solvefor x,y^2=r^2-x^2 ?

The solutions to the equation solvefor x,y^2=r^2-x^2 are x=sqrt(-y^2+r^2),x=-sqrt(-y^2+r^2)

Find the zeros of solvefor x,y^2=r^2-x^2

The zeros of solvefor x,y^2=r^2-x^2 are x=sqrt(-y^2+r^2),x=-sqrt(-y^2+r^2)

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solve for

x, y^{2} = r^{2} - x^{2}

x = - y^{2} + r^{2}, x = - - y^{2} + r^{2}

Solution steps

y^{2} = r^{2} - x^{2}

Switch sides

r^{2} - x^{2} = y^{2}

Move

r^{2}

to the right side

- x^{2} = y^{2} - r^{2}

Divide both sides by

- 1

x^{2} = - y^{2} + r^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - y^{2} + r^{2}, x = - - y^{2} + r^{2}

- \frac{1}{5} x^{2} + 2 x - 4 = 0

- x^{2} - 5 x + 6

\frac{1}{2} x^{2} - 5 = - x^{2} + 4.5

2 c^{2} + 15 = - 11 c

21 x^{2} + x - 10 = 0

What are the solutions to the equation solvefor x,y^2=r^2-x^2 ?
The solutions to the equation solvefor x,y^2=r^2-x^2 are x=sqrt(-y^2+r^2),x=-sqrt(-y^2+r^2)
Find the zeros of solvefor x,y^2=r^2-x^2
The zeros of solvefor x,y^2=r^2-x^2 are x=sqrt(-y^2+r^2),x=-sqrt(-y^2+r^2)