What is (3a-5)/8*(2a+2)/(3a^2-2a-5) ?

The solution to (3a-5)/8*(2a+2)/(3a^2-2a-5) is 1/4

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simplify (3a-5)/8*(2a+2)/(3a^2-2a-5)

simplify

\frac{3 a - 5}{8} \cdot \frac{2 a + 2}{3 a ^{2} - 2 a - 5}

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\frac{3 a - 5}{8} \cdot \frac{2 a + 2}{3 a ^{2} - 2 a - 5}

Cancel

\frac{2 a + 2}{3 a ^{2} - 2 a - 5} : \frac{2}{3 a - 5}

= \frac{3 a - 5}{8} \cdot \frac{2}{3 a - 5}

Cross-cancel common factor:

3 a - 5

= \frac{2}{8}

Cancel the numbers:

\frac{2}{8} = \frac{1}{4}

= \frac{1}{4}

17 k^{2} - 221 k = 0

3 z^{2} - 8 z + 2 = 0

n^{4} + 8 n^{2} + 15

(x - 1)^{\frac{1}{3}} - (x^{2} - x) (x - 1)^{- \frac{2}{3}}

e^{3 l n (3)}

What is (3a-5)/8*(2a+2)/(3a^2-2a-5) ?
The solution to (3a-5)/8*(2a+2)/(3a^2-2a-5) is 1/4