What are the solutions to the equation 3x^2-12x+3=0 ?

The solutions to the equation 3x^2-12x+3=0 are x=2+sqrt(3),x=2-sqrt(3)

Find the zeros of 3x^2-12x+3=0

The zeros of 3x^2-12x+3=0 are x=2+sqrt(3),x=2-sqrt(3)

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3 x^{2} - 12 x + 3 = 0

x = 2 + 3, x = 2 - 3

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

3 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 3 = 63

x_{1, 2} = \frac{- ( - 12 ) \pm 6 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 3}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6 3}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6 3}{2 \cdot 3} : 2 + 3

x = \frac{- ( - 12 ) - 6 3}{2 \cdot 3} : 2 - 3

The solutions to the quadratic equation are:

x = 2 + 3, x = 2 - 3

∣ x - 1 ∣ > ∣ 2 x - 1 ∣

x^{2} - x - 72 = 0

x^{2} + 3 x + 8 = 0

(x + 8)^{2} + (x - 6)^{2} = (x + 12)^{2}

(10 \frac{x}{6}) (10 \frac{x}{8}) = 1 0^{10}

What are the solutions to the equation 3x^2-12x+3=0 ?
The solutions to the equation 3x^2-12x+3=0 are x=2+sqrt(3),x=2-sqrt(3)
Find the zeros of 3x^2-12x+3=0
The zeros of 3x^2-12x+3=0 are x=2+sqrt(3),x=2-sqrt(3)