What are the solutions to the equation (x-6)^2+2(x-6)-8=0 ?

The solutions to the equation (x-6)^2+2(x-6)-8=0 are x=8,x=2

Find the zeros of (x-6)^2+2(x-6)-8=0

The zeros of (x-6)^2+2(x-6)-8=0 are x=8,x=2

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(x - 6)^{2} + 2 (x - 6) - 8 = 0

x = 8, x = 2

Solution steps

(x - 6)^{2} + 2 (x - 6) - 8 = 0

Expand

(x - 6)^{2} + 2 (x - 6) - 8 : x^{2} - 10 x + 16

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

∣ 2 x - 3 ∣ < 7

x^{2} = 5 x + 36

4 x^{4} + 4 x^{3} - 9 x^{2} - x + 2 \leq 0

8 x^{2} + 17 x + 2 = 0

2 x^{2} + 8 x - 18 = 0

What are the solutions to the equation (x-6)^2+2(x-6)-8=0 ?
The solutions to the equation (x-6)^2+2(x-6)-8=0 are x=8,x=2
Find the zeros of (x-6)^2+2(x-6)-8=0
The zeros of (x-6)^2+2(x-6)-8=0 are x=8,x=2