What are the solutions to the equation 6X+X-8X=10X-6XX+4 ?

The solutions to the equation 6X+X-8X=10X-6XX+4 are X=-(-11+sqrt(217))/(12),X=(11+sqrt(217))/(12)

Find the zeros of 6X+X-8X=10X-6XX+4

The zeros of 6X+X-8X=10X-6XX+4 are X=-(-11+sqrt(217))/(12),X=(11+sqrt(217))/(12)

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6 X + X - 8 X = 10 X - 6 XX + 4

X = - \frac{- 11 + 217}{12}, X = \frac{11 + 217}{12}

Decimal Notation

X = - 0.31090 \dots, X = 2.14424 \dots

Solution steps

6 X + X - 8 X = 10 X - 6 XX + 4

Expand

10 X - 6 XX + 4 : 10 X - 6 X^{2} + 4

- X = 10 X - 6 X^{2} + 4

Switch sides

10 X - 6 X^{2} + 4 = - X

Move

X

to the left side

- 6 X^{2} + 11 X + 4 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 6 ) \cdot 4}{2 ( - 6 )}

1 1^{2} - 4 (- 6) \cdot 4 = 217

X_{1, 2} = \frac{- 11 \pm 217}{2 ( - 6 )}

Separate the solutions

X_{1} = \frac{- 11 + 217}{2 ( - 6 )}, X_{2} = \frac{- 11 - 217}{2 ( - 6 )}

X = \frac{- 11 + 217}{2 ( - 6 )} : - \frac{- 11 + 217}{12}

X = \frac{- 11 - 217}{2 ( - 6 )} : \frac{11 + 217}{12}

The solutions to the quadratic equation are:

X = - \frac{- 11 + 217}{12}, X = \frac{11 + 217}{12}

x^{2} = \frac{7}{4}

7 t > 84

4 x^{2} + 10 x + 4 = 0

j^{2} - 5 j - 14

3 x + 5 = 2

What are the solutions to the equation 6X+X-8X=10X-6XX+4 ?
The solutions to the equation 6X+X-8X=10X-6XX+4 are X=-(-11+sqrt(217))/(12),X=(11+sqrt(217))/(12)
Find the zeros of 6X+X-8X=10X-6XX+4
The zeros of 6X+X-8X=10X-6XX+4 are X=-(-11+sqrt(217))/(12),X=(11+sqrt(217))/(12)